Question

Factor completely: 35x2 -x - 6

a. (7x- 3)(5x + 2)
b. (7x + 3)(5x- 2)
c. (7x- 6)(5x + 1)
d. (7x + 6)(5x- 1)

Answer 1

35x^(2)-x-6

For a polynomial of the form ax^(2)+bx+c, find two factors of a*c (-210) that add up to b (-1).In this problem (2)/(5)*-(3)/(7)=-(6)/(35) (which is (c)/(a)) and (2)/(5)-(3)/(7)=-(1)/(35) (which is ((b)/(a)) , so insert (2)/(5) as the right hand term of one factor and -(3)/(7) as the right-hand term of the other factor.
(x+(2)/(5))(x-(3)/(7))

Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
(5x+2)(7x-3)

Answer 2

a. (7x- 3)(5x + 2)

Answer 3

thanks !

Answer 4

np