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AC=3x and BC=5x. If the perimeter of triangle ABC is 84, then x=
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(a)=21 (b)=36 (c)=39 (d)=41 (e)=45
The hypotenuse and one leg are given. The missing leg is needed for the perimeter. If you know the Pythagorean triples, then you know that 3, 4, 5 is a Pythagorean triple as 3x, 4x, and 5x would be.
3x + 4x + 5x = 84 Solve for x. @aristine
oops, wrong problem: (a) 21/4 (b) 28/3 (c)4 (d)7 (e)12
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so it's d?
You could use the Pythagorean theorem to crank out the missing side. I will attach a "blurb" about Pythagorean triples in case you want to know more about them.
>so it's d? I don't know. What did x turn out to be?
7
Then, d is the correct option.
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thanks!
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