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factor this binomial; x^2-81
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(x-9)(x+9)
kanwar you should stop posting direct answer and help these people learn
thanks i hate factoring -.- and is there any steps to it?
what your looking for is a number that multiples to -81 and adds up to zero
OHHHH OK I GET IT thanks :)
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any binomial will have the form \[x^{2}+(a+b)*x+(a*b)\]
do you see how the term in front of x is a+b and the last term is a*b
(x-9)(x+9) we know this because to get [x ^{2}\] you have to multiply x.x and since the 81 is negative, the only way you can get that is by multiplying a positive times a negative. when you multiply this out to check yourself, you'll find the +9x term and -9x term cancel, giving you x^2-81
yes thank you everyone !
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