factor this binomial;
x^2-81

Question

factor this binomial;
x^2-81

anonymous · Answer

(x-9)(x+9)

anonymous · Answer

kanwar you should stop posting direct answer and help these people learn

anonymous · Answer

thanks i hate factoring -.- and is there any steps to it?

anonymous · Answer

what your looking for is a number that multiples to -81 and adds up to zero

anonymous · Answer

OHHHH OK I GET IT  thanks :)

anonymous · Answer

any binomial will have the form 
$$x^{2}+(a+b)*x+(a*b)$$

anonymous · Answer

do you see how the term in front of x is a+b and the last term is a*b

anonymous · Answer

(x-9)(x+9)
we know this because to get [x ^{2}\] you have to multiply x.x and since the 81 is negative, the only way you can get that is by multiplying a positive times a negative.  when you multiply this out to check yourself, you'll find the +9x term and -9x term cancel, giving you x^2-81

anonymous · Answer

yes thank you everyone !