Question

Write the equation of the ellipse 4x2 + 9y2 – 16x – 126y + 421 = 0 in standard form.

Answer 1

1. Move the 421 to the right side.
2. Group the x^2 term and the x term together and factor out the 4.
3. Group the y^2 term and the y term together and factor out the 9
4. Complete the square twice.
5. Factor

Answer 2

Thank you! xoxo

Answer 3

yw

Answer 4

Is it working out for you?

Answer 5

I got stuck on the factoring part.

Answer 6

Perhaps I can help.

Answer 7

\[4(x^2-4x+4)+9(y^2-14y+49)=-421+16+441\]

Answer 8

\[4(x+2)^2+9(y-7)^2=36\]

Answer 9

Whoops. Make that x-2

Answer 10

Okay, that makes sense. I've always been bad at factoring. Thank you/

Answer 11

\[\frac{(x-2)^2}{9}+\frac{(y-7)^2}{4}=1\]