Question

find 3 consecutive odd intergers whose sum is 249

Answer 1

Let the first odd no be (a-2), 2nd consecutive odd no is then (a-2)+2=a
and the third consecutive add no is (a+2).
so the 3 consecutive odd nos are : a-2, a ,a+2

For example,
3 is an odd no. (which is like a)
The consecutive odd nos. before and after 3 are:
3-2=1 which is like (a-2)
and 3+2=5 and this one is like (a+2)

Hence,proceeding with the question which says the summation of the 3 consecutive odd nos give 249,
(a-2)+a+(a+2)=249
Simplifying,
a-2+a+a+2=249
=>3a=249
=>a=83

Therefore,
a=83
a-2=81
a+2=85
Hence the 3 consecutive odd nos are:
81,83,85