Question

2. What is the area of the figure below?

(1 point)
45 in.²
90 in.²
135 in.²
180 in.²

Answer 1

plz help !

Answer 2

954 inches sq.

Answer 3

The figure is comprised of 4 congruent triangles each with :
base(b)=6in
altitude(a)=7.5in
Area of a triangle=\[a \times b \times \frac{ 1 }{ 2}\]
Hence area of each triangle= \[7.5\times6\times \frac{ 1 }{ 2}\]
=22.5 sq in.

Therefore area of 4 such triangle(or the figure itself)= \[22.5\times4=90\]
Answer=90 sq. in

If any problem in understanding the explanation please tell me.

Answer 4

thanks :) will you help me with one more ?

Answer 5

5. What is the area of the figure below?

(1 point)
7.5 m²
15 m²
21.25 m²
42.5 m²

Answer 6

okay..just a few mins please

Answer 7

ok im waiting

Answer 8

By congruency we shall find that the 2 triangles in the upper half of the figure and the 2 triangles in the lower half are respectively congruent.
So
1 triangle in the upper half=
base=2.5 m
altitute=2.5m too (isosceles triangle..hence base and height are of same length)
area=2.5\[2.5\times2.5\times \frac{ 1 }{ 2}=3.125\]
2 such triangles in the upper half= 3.125 * 2= 6.25 sq m.

1 triangle in the lower half=
base=2.5 m
altitute=6m
area=7.5 sq m
2 such triangles in the upper half= 7.5 * 2= 15 sq m
Therefore total area of figure= 6.25+15= 21.25 sq m

Sorry for the wait

Answer 9

thanks alot :)

Answer 10

Welcome..:)