Factoring trinomial completly.... y^3-12y^2+32y
y(y-4)(y-8)
Simplifying the exp : =y(y^2 -12y +32) =y(y^2 -4y -8y +32) =y{ y(y-4) -8(y-4) } =y{ (y-8)(y-4) } =y(y-8)(y-4)
thank you i have 5 more like that mind helping me out? @anikhalder and @jmprz_793
will try my best..need to show the working or just the answer?
4c^2+4c-15 and 4x^2-2x^2-12x answer is fine thank you @anikhalder
first one is (2c-3)(2c+5) but in the second question is it 4x^2 or 4x^3? @JazminZamarripa
sorry its 4x^3-2x^2-12x @anikhalder
also x^3-512 its factoring
2nd answer is 2x(2x+3)(x-2) @JazminZamarripa
x^3-512= (x-8)(x^2+8x+64
)
512=8^3 so exp: x^3-8^3 =(x-8)(x^2 +8x + 64) (used the formula \[a^{3}-b^{3}=(a-b)(a ^{2} +ab + b ^{2})\]
Thank you very very much can you help me on some more please=) @anikhalder
i guess you don't want my help :( @JazminZamarripa haha
oh sorry aha i thought you were offline=P want to help me? @jmprz_793
Solve... How would you solve this? 2x^2+4x=6
I have to find what x equals
2x(x+2)=6 ;p x=-3 x=1
Thumbs up @jmprz_793
aha=) thanks \[\frac{ x ^{2} }{ x ^{2}+6 }\times \frac{ x+5 }{ x }\]
and \[\frac{ 5x ^{2}-25x }{ 3x-1 }\div \frac{ x-5 }{ 3x-1 }\]
@jmprz_793 and @anikhalder
2nd answer is 5x
x(x+5)/(x^2+6) first answer Not sure about this
\[\frac{ 9a ^{2} }{ 3a+7b }-\frac{ 49b ^{2} }{ 3a+7b }\]
(3a-7b)/(3a+7b)
the first one is (x^(2))/(x^(2)+6)+(5x)/(x^(2)+6)
Solve for x... \[\frac{ 3 }{ 1-x }=\frac{ 4 }{ 1+x}\]
x=1/7
@jmprz_793 how would i write that can you show me through the a drawing?
|dw:1363840747803:dw|
3(1+x)=4(1-x) =>3+3x=4-4x =>7x=1 =>x=1/7
Find domain of the function.... \[f(y)=\frac{ y+5 }{ y ^{2}-5y }\]
Sorry i ment this one (x^(2))/(x^(2)+6)+(5x)/(x^(2)+6)
domain:|dw:1363840979147:dw|
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