Question

find by implicit differentiation dy/dx : (3e^xy) - x = 0

Answer 1

is it like this :
3e^(xy) - x = 0 ?
if yes, differentiation implicitly is
3ye^(xy) + 3xe^(xy) y ' - 1 = 0
3xe^(xy) y ' = 1 - 3ye^(xy)
y ' = {1 - 3ye^(xy)}/3xe^(xy)