Question

How do you determine the inverse of this relation f(x)=1/(x-2)+3

Answer 1

f(x)=1/(x-2)+3

y = 1/(x-2)+3 ... replace f(x) with y

x = 1/(y-2)+3 ... swap x and y

Now solve for y

Answer 2

x = 1/(y-2)+3

x - 3 = 1/(y-2)

(x - 3)(y-2) = 1

y-2 = 1/(x-3)

y = 1/(x-3) + 2