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OpenStudy (anonymous):
integral of (1/x^2). Why is the answer negative ?
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OpenStudy (anonymous):
integral of x^n is x^n+1 so 1/x^2 is x^(-2) so its integrtn is x^(-1)/(-1)
OpenStudy (anonymous):
1/x^2 =x^-2
OpenStudy (anonymous):
sorry frst line (x^(n+1))/(n+1)
Parth (parthkohli):
The answer is not necessarily negative... depends on the value of \(x\)
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