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Solve using matrices. 4x + 5y = 40 x – y = 1
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\[\left[\begin{array}{cc|c}4&5&40\\1&-1&1\end{array}\right]\]
\[R_1\to R_1-3R_2\]\[\left[\begin{array}{cc|c}1&8&37\\1&-1&1\end{array}\right]\] \[R_2\to R_2-R_1\]\[\left[\begin{array}{cc|c}1&8&37\\0&-9&-36\end{array}\right]\]
can you tell me what the next row operation will be ?
|4 5||x| |40| | || |=| | |1 -1||y| |1 | find inverse of |4 5| | | |1 -1| and then multiply both sides and find x and y
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