Question

Someone please help,
Simplify 8 to the negative 1 third power

Answer 1

do you mean
\[(8^{-1})^{3}\] ??

Answer 2

\[8^{-1/3}=(\frac{ 1 }{ 8 })^{1/3}=\sqrt[3]{1/8}=1/2\]

Answer 3

8^(-1/3)

x^-1 = 1/(x^1)

so 8^(-1/3) = 1/(8^(1/3))

8 = 2^3

so

1/((2^3)^(1/3))

equals

1/((x^3*(1/3)))

equals

1/x^(3/3)

equals

1/x^1

equals

1/x

Answer 4

Perfect answer @yuendat99 ... it is actually .5

Answer 5

Thanks guys. (:

Answer 6

for some reason i substituted an x instead of my 2 so at the end it is 1/2

Answer 7

Okay thanks