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reparametarize the curve "alpha" in alpha(t)=(e^t,e^-t,2t) using h(s)=logs on j:s>o
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Do you mean t=logs?
exactly
yes
OK, so \(\alpha(s)=(e^{\log s}, e^{-\log s}, 2\log s) \). I think that you also mean that \(\log s= \log_{e}s=\ln s\)...if so, you can simplify easily.
what is the answer?
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