Question

For questions 3 and 4, sketch the graph of the tangent curve in the interval from 0 to 2pi. the questions are
3. y = tan 4/3 Θ (1point)
4. y = tan (–2Θ) (1 point)

please help me understand and answer this question if you could please and thank you so much :)

Answer 1

3. you have the number stands before theta is 4/3. it means the period of function is Pi/4/3 = 3Pi/4. for tangent function the graph with period 3pi/4 can be drawn as attachment. the way you do is dividing 3Pi/4 by 2 you get the half of period: 3Pi/8 . take 0 as middle point. back to the left 3Pi/8 to get -3Pi/8 point. then from 0 go to the right exactly 3Pi/8 to get another point. draw out the graph