A ball is thrown from the ground at a velocity of 64 feet per second. The formula h = –16t2 + 64t gives the ball’s height, in feet, after t seconds. How many seconds will it take the ball to reach its maximum height?

Question

anonymous · Answer

max is at the vertex, first coordinate of the vertex of a parabola (which is what you are looking for) is always $-\frac{b}{2a}$ which in your case is 
$$-\frac{64}{2\times (-16)}$$

anonymous · Answer

better known as 2

anonymous · Answer

Can you answer this one? : What is the y-intercept of the function that passes through the points (–3, 12) and (4, –2)?