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Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x ?
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\[\frac{ 3 }{ 3x }+\frac{ 1 }{ x+4 }=\frac{ 10 }{ 7x }\]
3/3 = 1
So then
\[\frac{ 3 }{ 3x } becomes x\]
1/x + 1/(x+4) = (10/7)*(x) // multiply through by x 1 + x/(x+4) = 10/7 x/(x+4) = 10/7-1 x/(x+4) = 3/7 x = (3/7)(x+4) x = (3/7)x + (12/7) x-(3/7)x = 12/7 (4/7)x = 12/7 multiply both sides by 7/4 x = (12/7)*(7/4) x = 12/4 = ?
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so, x=3?
or should the sign be reversed, making x=-3?
x = 3
okay, thanks!
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