Question

I have filled a bag with differently colored ping-pong balls. There are twenty balls in the bag. Twelve are white, six are orange and two are pink. When I draw a ball from the bag, I remove it. What is the probability that my first draw is a white ball and my second is not?

A) 0.240

B) 0.253

C) 0.400

D) 0.421

Answer 1

it means asking to P(White and Orange) + P(White and pink)
= 12/20 * 6/19 + 12/20 * 2/19
= 72/380 + 24/380
= 96/380
= 0.2526..
= 0.253

Answer 2

Thanks so much

Answer 3

you're welcome :)