Question

find the exact value of sin^-1 (1/2),-Π/2 ≤ x ≤ Π/2

Answer 1

\[x=\sin^{-1}\frac{1}{2}\]
\[\sin x=\frac{1}{2}\]
so x=pi/3 for the given range

Answer 2

can you give me the answer it's my test ? i have to summit tomaroo

Answer 3

is that the answer?

Answer 4

sorry it is: x=pi/6 (30degrees)

Answer 5

what do i put for answer?

Answer 6

pi/6

Answer 7

thank you very much
can i ask you one more it's similar ?

Answer 8

yes

Answer 9

sketch the graph of y = 3sec (x - Π/2) for -2Π ≤ x ≤ 2Π

Answer 10

help me please

Answer 11

what is cos(-x) ?

Answer 12

1/y i think

Answer 13

cos(-x)=cosx
and so is sec(-x)=secx

and what is cos(pi/2 - x)?

Answer 14

is it 0.9997468666
am i right
?

Answer 15

cos(pi/2 - x)=sinx

Answer 16

i think you need to clear your basics first

Answer 17

ow

Answer 18

i am totaly dumb on math

Answer 19

i do try hard but it just don't go through my head

Answer 20

in which class are you?

Answer 21

precalculus
i don't know y i has the class even

Answer 22

i mean in which grade are you?

Answer 23

11

Answer 24

then you can make it,there is nothing too hard in maths

Answer 25

just you have to make visibility in concepts

Answer 26

i guess i suck at that

Answer 27

are you on college?

Answer 28

can you give me answer of that question
it's the end of quater tomaroo i need to pass this test inorder to pass on class?
please