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Mathematics 17 Online
OpenStudy (anonymous):

what is the length of the transverse axis of (x+2)^2/16-(y-3)^2/9=1

OpenStudy (anonymous):

a^2 = 16 b^2 = 9 transverse axis : 2a conjugate axis : 2b so here transverse axis : 8 conjugate axis : 6

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