Question

In a school of 300 students, 260 students take physics and 185 students take calculus. How many students take both physics and calculus if we know that every student takes at least one of the courses? Any help would be great, thanks!

Answer 1

Let P and C be the set representing students who have taken physics and calculus respectively.

\[n(P)=260\]
\[n(C)=185\]
\[n(PUC)=300\]
\[n(Pint.C)=?\]

Answer 2

n(P U C)=n(P)+n(C)-n(P int. C)

Answer 3

substitute values , (int. means intersection)

Answer 4

thanks so much!