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Mathematics 8 Online
OpenStudy (kamille):

Hello, really easy question: There are 3 children and 5 gifts. Parents gives one gift to one children, How many ways they can give it? I think: 5*4*3=120 is it correct?

OpenStudy (kamille):

@Mertsj

OpenStudy (kamille):

haha made lots of mistakes in the problem: Parents gives one gift to one children= Parents give one gift to one child

OpenStudy (kamille):

@wio

OpenStudy (kamille):

@abhi7 can you help me?

OpenStudy (kamille):

@vedic someone!

OpenStudy (anonymous):

Yes ur answer is correct!

OpenStudy (anonymous):

yup it seems ryt to me.... because first child 5 options... second child 4 options.. third child 3 options.... so 5*4*3=120

OpenStudy (kamille):

oh, thank you. I still can't find connection between where I should find C and where i should write A . Can someone explain me?

OpenStudy (kamille):

for exemple: There are 5 gifts. From this gift you need to make one big present formed of 3 smaller ones (of these 5 gifts). How many presents can be made?

OpenStudy (kamille):

I think now I need to find C?

OpenStudy (anonymous):

when there is arrangement we use permutation n when there is choice we use combination...

OpenStudy (kamille):

well, the problem, I can't understand where is arrangment and where is not?

OpenStudy (anonymous):

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