Question

solve for x over the inverval [0, 2π)

1) cos²x+ 2cosx-3 =0

2) (tanx-1) (cosx+1) =0

3)3sec3x-2√3 =0

Answer 1

i just need help with number 3

Answer 2

third is simple to just keep sec3x on lhs and take rest on rhs..

Answer 3

is that\[3\sec3x-2√3 =0 \]
if it is then