Question

find the indentical expression for the following: sinx(secx-cotx)

Answer 1

well sec = 1/cos and cot = 1/tan = cos/sin

so multiplying it out gives

\[\frac{\sin(x)}{\cos(x)} - \frac{\sin(x) \cos(x)}{\sin(x)} = \tan(x) - \cos(x)\]

Answer 2

thank you for the help