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How would I do this???? Help? The length of a rectangle is 1ft more than twice its width, and the area of the rectangle is 28ft^2 . Find the dimensions of the rectangle.
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Let the width of the rectangle be x We have the information: "The length of a rectangle is 1ft more than twice its width," Then the length would be 2x+1|dw:1364018342800:dw| Can you try to solve for x?
3x
width=x and length=2x+1 area of rectangle=lenth*width x(2x+1)=28 2x^2+x-28=0 or x^2+1-14=0
sorry x^2+x-14=0
now solve it to get the x
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sorry the equation should be 2x^2+x-28=0
width =7 and length=15
sorry width=3.5 and length= 8
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