Question

repost

Answer 1

the instructions are wierd to me .... i assume its saying that a student wishes to schedule his classes, and that he cannot take 2 or more classes that are running at the same time

Answer 2

I thiught thats what I did in my last one!

Answer 3

its a continuation :)

Answer 4

I confused, too. when solving for chromatic, and put back into the original one, we get A,G and then BC (the same color) cannot be the same time. they are in conflict table.

Answer 5

@Hoa so was I right?

Answer 6

let me go back to yesterday post

Answer 7

there are many different ways to color a graph; you prolly want to color it so that it matches the given chart

Answer 8

I thought there was one odd and one evn cycle

Answer 9

No friend.!! we solve the problem and can use many methods but the problem must be solved without conflict with the method we use. is it right?

Answer 10

@electrokid what you mean by odd cycle and even one?

Answer 11

remeber the way I drew it, in there, the line crossing in the middle splits the graph to teo cyclic path, one odd and one even.

Answer 12

@amistre64 I coonected the graph when they have conflicts.

Answer 13

so you drew up a complement :) right?

Answer 14

yes!!

Answer 15

no.. you drew a compliment! lol

Answer 16

hey, compliment or complement?

Answer 17

tomato tomato :)