Question

R(x)=80x-x^2/x^2+80. wht level of prod results in max revenue? wht is the max rev?

Answer 1

Make sure you use parentheses when you type equations like this. Guessing it's \[\large R(x) = \frac{80x-x^2} {x^2+80}\] but i have no idea to be sure.

You'll have to differentiate the R(x), and find where R'(x) = 0, as this will be where there is a maximum

(you can check the second derivative R''(x) is negative at that point, to check that it's indeed a maximum)