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Mathematics 13 Online
OpenStudy (anonymous):

Six identical circles are arranged,as shown in the figure. The circles touch the sides of a large rectangle as well as each other. The vertices of the small rectangle coincide with the centres of four of the circles. The perimeter of the small rectangle is 60 cm.What is the perimeter of the large rectangle?

OpenStudy (anonymous):

@campbell_st

OpenStudy (mathstudent55):

Figure?

OpenStudy (campbell_st):

is there a figure...go figure

OpenStudy (anonymous):

|dw:1364104316658:dw|

OpenStudy (mathstudent55):

Can you figure out the diameter of each circle?

OpenStudy (campbell_st):

ok... the the perimeter of the small recatangle is 60 so let d be the diameter of the circles.. so 2d in the length of the small reactangle and 1 d is the width. so 60 = 2d + 2d + d + d solve for d now the large reactangle has length 3d and width 2d so P = 3d + 3d + 2d + 2d P = 10d hope this helps.

OpenStudy (anonymous):

Nope its not given @mathstudent55

OpenStudy (mathstudent55):

|dw:1364104632823:dw|

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