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What is the simplified form of the quantity x-squared minus 16 over the quantity x plus 4 ?
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\[\frac{ x^2-16 }{ (x+4) }\]
\[\dfrac{x^2 - 16}{x+4}\] I'd factor the numerator if I were you.
Remember the differences of squares? \[x^2 - a^2 = (x-a)(x+a)\]
so then, the numerator would be \[(x+4)(x-4)\]right?
Right.
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and then the (x+4) would cancel each other out
Yes
leaving the answer as x - 4, with the restriction x ≠ -4
Yeah.
Thanks!
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Glad I helped.
x-4, I did that one in my head
Good for you.
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