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Linear Algebra
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What is the simplified form of the quantity 4 z squared minus 16z plus 15 over the quantity 2 z squared plus z minus 15 ?
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\[\frac{ 4z^2-16z+15 }{ 2z^2+z-15 }\] is it yours?
since Calisto here, let him help. hihi... he is much more better than me
@DeadShot Are you here? Is the expression given by Hoa right?
Suppose the expression is correct. To simplify it, we need to factorize both the numerator and denominator. Consider the numerator, \[4z^2-16z+15\]\[=4z^2-10z-6z+15\]Take out the common factor for the first two terms and last two terms: \[=2z(2z-5)-3(2z-5)\]Take out the common factor again, we'll get \[=(2z-3)(2z-5)\] Now, try to factorize the denominator.
\[So-the- answer -is\frac{ (2z-3) }{ (z+3) } \]right?
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