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Factor 4m^16 – 12m^8p^3 + 9p^6 completely. A. (2m^4-3p^3)^2 B. (2m^8-3p^3)^2 C. (2m^8-3p^6)^2 D. 4(m^4-3p^3)^2
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Please help!
\(4m^{16} - 12m^8 p^3 + 9p^6\) Can I write the above equation in the form : \(a^2 -2ab + b^2\) ?
\(4m^{16} = a^2\) Can you tell me what is \(a\) now?
I am not sure about the answer
can I write \(4m^{16} \) as \((2m^8)^2\) ?
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Yes
@mathslover
Now : What can you write \(9p^6\) as : in the form of \(\boxed{\textbf{(__)^2}}\)
(3p3)^2
Is it correct? @mathslover
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Yeah \((3p^3)^2\) Good job.
now can I write \(-12m^8 p^3\) as \(-2(2m^8)(3p^3)\) ... ?
Yes
Is the right answer B?
Yeah @RH good work.
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Thank you! :)
You're welcome and keep up your practices.
Thank you! I will ! :)
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