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Mathematics 14 Online
OpenStudy (anonymous):

Factor 5a^4 – 5a completely. A. 5a(a – 1)(a^2 + a + 1) B. 5a(a^3) C. 5a(a + 1)(a^2 – a + 1) D. 5a(a – 1)(a + 1)

OpenStudy (anonymous):

Help? anyone

OpenStudy (anonymous):

it's the first one, A.

OpenStudy (anonymous):

5a^4-5a = 5a(a^3-1)=5a(a-1)(a^2+a+1)

OpenStudy (anonymous):

you have the formula\[ a^{3} +/- b^{3} = (a +/- b)(a^{2} -/+ ab + b^{2})\]

OpenStudy (anonymous):

Thank you!!!! I understand it now! THANKS :)

OpenStudy (anonymous):

you're welcome. :)

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