Question

cscx/cosx - cosx/sinx. simplify as much as possible

Answer 1

\[\csc x=\frac{1}{\sin x}\\
\frac{\csc x}{\cos x}-\frac{\cos x}{\sin x}=\frac{1}{\cos x\sin x}-\frac{\cos x}{\sin x}\\
= \frac{1-\cos^2 x}{\cos x\sin x}\]
you can go from there, right?

Answer 2

the answer should be \(\tan x\)

Answer 3

yess thank you!!!

Answer 4

:)