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How do you solve sin^-1 ((√2)/2)?
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Can you use a calculator?
\[\sin^{-1} (\frac{ \sqrt{2} }{ 2 })\]
@Insist do you know the value of sin 45 degrees?
A simple one
How do you find it. o;
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Trigonometry is so easy :)
@Insist \[\sin 45=\frac 1{\sqrt 2}\] Could you simplify this? \[\frac{\sqrt 2}2\]
You can't simplify that, but how did you find sin 45
\[\frac{\sqrt 2}{2}=\frac 1 {\sqrt 2}\]
sin 45, it's a standard value of trigonometric ratios. It's the sin for a right triangle with equal sides|dw:1364149596151:dw|
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