Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <2, -4>, v = <3, -8>

Answer 1

\[\cos \Theta = \frac{ 6+48 }{ \sqrt{20}\sqrt{75} }\]

Answer 2

now simplify

Answer 3

\[\cos \Theta = \frac{ 54 }{ 10\sqrt{15} }\]

Answer 4

it only gives me degrees:
A) 3.0°

B) 6.0°

C) -7.0°

D)16.0°
As answers and i don't know how to change all of that into a degree