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Help finding f^-1(x)
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\[f(x)\sqrt[3]{x-8}\]
write it like y= \(\sqrt[3]{x-8}\) then cube both sides, what u get ?
cube each side?
so f^-1 would look like y = cubed root of x - 8 x = cubed root of y -8 so you would cube both sides x^3 = y-8 add 7 to both sides y = x^3 + 8 ??
that seems correct to me. good work :)
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oh wow lol thanks!
welcome ^_^
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