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Mathematics 9 Online
OpenStudy (anonymous):

please help me... n(n-6)+3(n-6)

Directrix (directrix):

What are the instructions for this problem?

OpenStudy (anonymous):

to factor

Directrix (directrix):

This is factoring by grouping. The common factor is (n - 6). So, take it out so: n(n-6)+3(n-6)= (n - 6) * [ ? + ?]

OpenStudy (anonymous):

(n-6)(n+6)???

Directrix (directrix):

(n - 6) * (n + 3) @taishacasseus30

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