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Algebra
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vertex of f(x)=(x+3)^2
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Well, you're in luck When you have your parabola in this form f(x) = (x - h)² + k Then your vertex is at the point (h , k)
Yea but what are the numbers?
What indeed... ;) Observe it more carefully... f(x) = (x+3)² f(x) = (x-h)² + k So what are h and k?
-3, 0?
There you go ^.^
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