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Mathematics 16 Online
OpenStudy (anonymous):

(x+1)/(3x+6)*(x^2+x-2)/(x^2-x-2) Can someone help me on this please.

OpenStudy (anonymous):

my guess is you are supposed to factor and cancel

OpenStudy (anonymous):

\[\frac{(x+1)(x^2+x-2)}{(3x+6)(x^2-x-2)}\]

OpenStudy (anonymous):

i think it factors as \[\frac{(x+1)(x+2)(x-1)}{3(x+2)(x+1)(x-2)}\]

OpenStudy (anonymous):

cancel what ever you can top and bottom

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