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If x*x + 2x - 35 = 0, then x = ?
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is \(xx\) supposed to be \(x^2\) ?
\[x^2+2x-35=0 \rightarrow (x+7)(x-5)=0 \implies x = -7,5\] @RAWFECTION
@genius12 Please refrain from posting answers. Please try to lead the asker to the answer
ok so u r not supposed to giv anybody the answer?
@Mertsj I am sorry. Usually I try to tell and explain and hint to what is the answer but sometimes I forget the no giving answer rule. I'll watch out next time.
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We try to lead the student to the answer if at all possible.
you could use the quadratic formula \[x^2+ 2x - 35 = 0\qquad\implies\qquad x_{1,2}=\frac{-2\pm\sqrt{2^2-4\times1\times-35}}{2\times1} \]
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