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Algebra
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OpenStudy (anonymous):
find the equation of the line that has the given properties write equation in slope intercept form
contains (3, 5) slope =7
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OpenStudy (anonymous):
y=mx+b
OpenStudy (anonymous):
so 5=1(5)+7
OpenStudy (anonymous):
?
OpenStudy (anonymous):
x = 3, y = 5, and m = 7. You're solving for b. So, 5 = 7*3 + b.
OpenStudy (anonymous):
21+7=28
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Directrix (directrix):
Use the point-slope general formula for a line:
y - y1 = m(x - x1) where m is the slope of the line and (x1, y1) is the point on the line.
Directrix (directrix):
y - y1 = m(x - x1)
y - (5) = 7( x - (3) )
y - 5 = 7x - 21
y = ?
@romoor93
Directrix (directrix):
Let me know what you get, okay?
OpenStudy (anonymous):
y=7x-26
Directrix (directrix):
>y=7x-26 Almost
----
y - 5 = 7x - 21
y -5 + 5 = 7x - 21 + 5
y = 7x - ? --> What is -21 + 5?
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OpenStudy (anonymous):
-16
Directrix (directrix):
Yes, so y = 7x - 16
OpenStudy (anonymous):
wow alot of steps but i think i get it
OpenStudy (anonymous):
thanks for steps
Directrix (directrix):
The steps are helpful to me. They will take you to the answer even if the walk is slow. :)
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