What is the equation of the line that passes through (4, -1) and (-2, 3)?

2x- 3y- 5 = 0
2x+ 3y- 5 = 0
-2x+ 3y- 5 = 0

Question

What is the equation of the line that passes through (4, -1) and (-2, 3)?

2x- 3y- 5 = 0
2x+ 3y- 5 = 0
-2x+ 3y- 5 = 0

mertsj · Answer

First find the slope.

anonymous · Answer

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Your answer is B, 2x+3y-5=0

anonymous · Answer

Find the slope and substitute into eq:$$y = mx + b$$
where m is the slope you will first calculate.
Using any one pair of points that you r given just pulg it into the eqquation, you eill get the "b" value.

Then you will have the equation.

anonymous · Answer

What is the slope of the line that passes through (-2, 7) and (4, 9)?

slope = -1/3
slope = 1/3
slope = 3