How many real number solutions are there to the equation 0 = –3x² + x – 4?

Question

terenzreignz · Answer

To get the answer to this type "How many real number solutions are there..." when your equation is quadratic... of the form 0 = ax² + bx + c
... 
well
First, I want you to calculate what's called the discriminant...
b² - 4ac
Can you do that?

anonymous · Answer

how?

terenzreignz · Answer

well
the form is
0 = ax² + bx + c
0 = -3x² + x - 4
So what are your values for a,b, and c?

anonymous · Answer

a is -3
b is 1
c is -4

terenzreignz · Answer

Well then, plug them into this formula (called the discriminant)
b² - 4ac
and tell me what you get.

anonymous · Answer

1^2-4(-3*-4)    = -47

terenzreignz · Answer

Nice.  Now, the discriminant is what tells you the number of real-numbered solutions you'll get.
If the discriminant is strictly positive, then you'd have two real number solutions.
If the discriminant is zero, then you'd get exactly one real number solution.
And if the discriminant is negative, then you will have no real number solutions at all :)

Hope this helped
Good hunting ^.^

anonymous · Answer

so 0 real number solutions?