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its easier for me to keep track of if the question is posted in the same window ... otherwise i tend to mix things up more than usual
what have you tried to work up so far?
since distance is equal to speed times time bus speed times time b, plus train speed times time t = 600km time a + time b = 9 hours we are given that the bus speed is train speed - 20 km/hr
we also have the condition that the bus traveled 3/5 of the way and the train traveled 2/5 of the way
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the bus travels 600*3/5 = 360 km the train travels 600*2/5 = 240 km speed x time = distance (train - 20) b = 360 train a = 240 a + b = 9 these can be used to solve it
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