Question

what is h(g(-12)) if f(x)=x^2, g(x)=X-1 and h(x)=4x?

Answer 1

\[h(g(x))=4[x-1] \therefore h(g(-12)) = 4[(-12)-1] \implies 4(-13)=-52 \therefore h(g(-12))=-52\]

Answer 2

Thank you so much!