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How can I solve this? The radius of a circular puddle is growing at a rate of 20 cm/s How fast is the area growing at the instant when it equals 1 cm^2?
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formula for the area is \(A=\pi r^2\)
take the derivative and get \[A'=2\pi r r'\] you are asked for \(A'\) and told \(r'=20\) and \(r=1\) so you can find \(A'\)
do I just plug in 20 into the equation?
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