Systems of Linear Equations

Solve the system below.

y = x2 – 4
y = –4

a.(0, –4)
b.(–4, 0)
c.(0, –4), (–4, 0)
d.There is no real solution.

Question

Systems of Linear Equations 

 Solve the system below.

y = x2 – 4
y = –4  

a.(0, –4)
b.(–4, 0)
c.(0, –4), (–4, 0)
d.There is no real solution.

snuggielad · Answer

one mistake...you used the term "solve" we can not solve it for you...i can help you though if you like

anonymous · Answer

please?

snuggielad · Answer

substitute the y in the first equation for the -4 and work it our solving for x

snuggielad · Answer

the second equation says y=-4 so you know thats y...now you just need to find x

snuggielad · Answer

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anonymous · Answer

how do i solve for x? i get -4=x2-4... do i subtract -4 from each side?

anonymous · Answer

oh and it's x^2

snuggielad · Answer

ok..thanks for telling me that...anyway you need to get the -4 off the rigt side so you need to cancel it out...so you have to add four to the negative four on both sides

anonymous · Answer

0=x^2?

snuggielad · Answer

x^2 =0 so x=0 because x*x = zero......
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anonymous · Answer

so x=0?
and y= -4
is it a?

snuggielad · Answer

that is correct the answer is 
(0,-4)
again

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PLEASE BEST MY ANSWER

anonymous · Answer

I 'bested' it. Thank you so much i understand this type of problem now.