-18x^3=-32x solve by factoring could anyone please help? I would greatly appreciate it
Hello :)
Hi! Could you please help me? I am having a lot of trouble solving this
Sure ,Lemme Type the answer :)
Okay, thank you
Thank you Jack for replying
\[-18x^3=-32x\] \[18x^3=32x\] b/c the negatives cancel out. \[18x^2=32\] b/c you can divide an x from each side \[9x^2=16\] b/c you can factour out the common term, 2 \[x^2=\frac{ 16 }{ 9 }\] \[x=\sqrt{\frac{ 16 }{ 9 }}\] \[x=\frac{ 4 }{ 3 }\] :)
You're welcome :)
Omg,After i wrote a whole page i clicked on restart by mistake !!!!!!!!
Does this make sense @Brookebrookiee ?
Well, except that you missed two of the three solutions.
@Brookebrookiee : Jack was soo close but he missed 2 answers
@Eyad oh geeze, that happens to me all the time, mate!
correct, My mistake.
Oh okay
@Brookebrookiee : follow the steps i will show u now
Okay, thnk you
Eyad?
@Eyad You there, mate?
i'am there
Ok just making sure
i'am writing the answer ,dont worry
-18x^3+32x=0 . ====>We will take a common factor which is -2x . -2x (9x^2+16) ====> now lets factorize the bracket . -2x (3x-4) (3x+4) ====> now lets equal each bracket to zero and get the value. -2x=0 , x=0 3x-4=0 , 3x=4 , x=4/3 3x+4=0 , 3x=-4 , x=-4/3 Therefore S.S= { 0,4/3 ,-4/3}
Sry it took soo long cuz if this lag !!
Any questions ?
Thank you both so much. I appreciate all of your help, and you too Jack.
I appreciate you both taking the time to respond :)
Of course! :D I'm glad I could help at all, even though I gave you only 1/3 of the answer
yw
Thank you! take care
And yourself.
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