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Triple integral of (4*cos(x^2))/(2*sqrt(z)), given that 2*y<=x<=2, 0<=y<=1, 1<=z<=4. I know that you have to use an infinite series for cos(x^2), and according to Maple the answer is sin(4). I can't seem to get that answer!
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\[\int\limits_{0}^{1}\int\limits_{1}^{4}\int\limits_{2y}^{2}(2\cos (x^2))/(\sqrt{z})dx dz dy\]
I"m going to have to give you a medal simply because that math looks so esoteric from where I'm at.
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