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How do i solve this guyz? o.O
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I need to solve this two equations. \[a r^{2} = 20----->1\] \[\frac{a}{1-r} = 3a\]
@.Sam. @robtobey
they're saying that \[T_3=20 \\ \\ S_\infty=3T_1\]
\[T_3=20 ...(1) \\ \\ S_\infty=3T_1 ...(2)\] \[(1)\\ \\ a_1r^{n-1}=30 \\ \\ a_1r^2=30 \\ \\ \text{We know that T_1=a_1} \\ \\ (2) \\ \\ \frac{a_1}{1-r}=3a_1 \\ \\ r=\frac{2}{3} \] Substitute r into (1) and you have a1
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thnks alot
yw
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