Question

How would I solve this equation for y?
(y-4)^2=2y^2-5y+12

Answer 1

open the square, remove constants

Answer 2

then, use formula x=-b+or-under root b^2-4ac over 2a

Answer 3

where ax^2+bx+c=0

Answer 4

y=1 or y=-4

Answer 5

thanks